如何讓Bash取出特定序數？ - Linux
By Daniel
at 2011-08-19T14:13
at 2011-08-19T14:13
Table of Contents
ls後有一堆長這樣子的檔案：
foo_001_bar
foo_002_bar
foo_004_bar
foo_005_bar
foo_007_bar
...
(注意序數不一定連續)
我想要像是指定[0-9]{3}的方法單獨取出「數字」，而不包括檔名中其他的東西；然後輸
出到$FILE_SERIAL陣列中:
001
002
004
005
007
...
原本想試試看用sed或awk做(我不知道方向有沒有錯誤...我是Shell Script初學者...)，
但Google看了很久還是不知道該如何只取出數字。
謝謝。
--
--
foo_001_bar
foo_002_bar
foo_004_bar
foo_005_bar
foo_007_bar
...
(注意序數不一定連續)
我想要像是指定[0-9]{3}的方法單獨取出「數字」，而不包括檔名中其他的東西；然後輸
出到$FILE_SERIAL陣列中:
001
002
004
005
007
...
原本想試試看用sed或awk做(我不知道方向有沒有錯誤...我是Shell Script初學者...)，
但Google看了很久還是不知道該如何只取出數字。
謝謝。
--
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--
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Linux
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