這是我修課時看到的
A client-server system uses a satellite network,with the satellite at a
height of 40,000 km.What is the best-case delay in response to a request?
解答寫request has to go up and down,and the response has to go up and down.
所以40000x4=16000km 16000/300000(光速)=533(msec)
我是覺得應該只要request go up to satellite,response 再go down, 應該只走了
40000x2,請問為什麼解答寫那樣呢?
各位高手有什麼見解?大感謝^^
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A client-server system uses a satellite network,with the satellite at a
height of 40,000 km.What is the best-case delay in response to a request?
解答寫request has to go up and down,and the response has to go up and down.
所以40000x4=16000km 16000/300000(光速)=533(msec)
我是覺得應該只要request go up to satellite,response 再go down, 應該只走了
40000x2,請問為什麼解答寫那樣呢?
各位高手有什麼見解?大感謝^^
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