IOTA真的能實現足夠的算力嗎 - 數位貨幣
By Lydia
at 2018-01-23T23:29
at 2018-01-23T23:29
Table of Contents
※ 引述《kugwa (苦瓜)》之銘言:
: 但運作方式有一處根本差異
: 新的交易被接到Tangle時 這筆交易並不會馬上使帳本更新
: 而是要等累積權重到達一定的量才會被帳本採用
: 也就是交易有confirmed的概念
: (我之前是用finalized這個字 這兩個字我當一樣意思來用)
: 交易confirmed之後就再也不會被撤銷了
: 這與Blockchain的「最長鏈的交易才被帳本採用 新區塊一接上最長鏈就立即更新帳本」
: 有著截然不同的性質
: 來看看Tangle如何防止雙花
: 其實有了上述概念之後應該不難理解
: 用互斥交易A跟B的例子來說明
: 假設大家走A的sub-tangle
: 當A的累積權重到達一定量被視為confirmed 才會被帳本採計
: 這時候再拿B後面跟一大串交易接到Tangle上是沒有意義的
: 因為B跟A互斥 而A已經confirmed 所以B不可能被帳本採計
感謝您的解釋
我大概明白您要表達的意思 但這跟IOTA的tangle網路特性似乎沒有相關
你說的這規則在現行區塊鏈也可以一樣比造辦理 但為什麼BTC等不使用這樣的機制
因為"當一個節點有了confirm過的交易 即使有更高權重的交易(鏈)出現它也不去承認"
這句話就是有中心化風險的
我們一開始的原命題是"沒有coordinator的存在"
那假設當一個新節點加入網路時 它錯過了以上發生的故事 只是單純想重新同步網路狀態
它會看到兩條鏈(sub-tangle)
一條是誠實節點堅守的總權重低但號稱是"誠實"的鏈
一條是高算力打造高權重的鏈
請問新節點在不預設哪個節點是可信任(也就是現在coordinator)的情況下
它是不是只能選擇高權重那條鏈?
--
: 但運作方式有一處根本差異
: 新的交易被接到Tangle時 這筆交易並不會馬上使帳本更新
: 而是要等累積權重到達一定的量才會被帳本採用
: 也就是交易有confirmed的概念
: (我之前是用finalized這個字 這兩個字我當一樣意思來用)
: 交易confirmed之後就再也不會被撤銷了
: 這與Blockchain的「最長鏈的交易才被帳本採用 新區塊一接上最長鏈就立即更新帳本」
: 有著截然不同的性質
: 來看看Tangle如何防止雙花
: 其實有了上述概念之後應該不難理解
: 用互斥交易A跟B的例子來說明
: 假設大家走A的sub-tangle
: 當A的累積權重到達一定量被視為confirmed 才會被帳本採計
: 這時候再拿B後面跟一大串交易接到Tangle上是沒有意義的
: 因為B跟A互斥 而A已經confirmed 所以B不可能被帳本採計
感謝您的解釋
我大概明白您要表達的意思 但這跟IOTA的tangle網路特性似乎沒有相關
你說的這規則在現行區塊鏈也可以一樣比造辦理 但為什麼BTC等不使用這樣的機制
因為"當一個節點有了confirm過的交易 即使有更高權重的交易(鏈)出現它也不去承認"
這句話就是有中心化風險的
我們一開始的原命題是"沒有coordinator的存在"
那假設當一個新節點加入網路時 它錯過了以上發生的故事 只是單純想重新同步網路狀態
它會看到兩條鏈(sub-tangle)
一條是誠實節點堅守的總權重低但號稱是"誠實"的鏈
一條是高算力打造高權重的鏈
請問新節點在不預設哪個節點是可信任(也就是現在coordinator)的情況下
它是不是只能選擇高權重那條鏈?
--
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