統計路徑內的檔案大小 - Linux

By Lauren
at 2016-07-27T14:09
at 2016-07-27T14:09
Table of Contents
請問一下
有無效快的方法可以計算路徑內一天內且是特定檔名增加的容量 及平均單檔的容量
小弟目前是用
find /mnt/filesystem/path -iname "*.exr" -o -iname "*.tga" -a -mtime 1 -exec ls
-l {} > day \;
先讓他輸出昨天的日期
然後
cat day | wc -l 算出有幾個檔案
cat dat | awk '{print $5}' | awk '{sum += $1} END {print sum/1024/1024}'
算出檔案大小(MB)
問題是 用find 通常會需要超過一小時 請問有無適合的方法
感謝
--
有無效快的方法可以計算路徑內一天內且是特定檔名增加的容量 及平均單檔的容量
小弟目前是用
find /mnt/filesystem/path -iname "*.exr" -o -iname "*.tga" -a -mtime 1 -exec ls
-l {} > day \;
先讓他輸出昨天的日期
然後
cat day | wc -l 算出有幾個檔案
cat dat | awk '{print $5}' | awk '{sum += $1} END {print sum/1024/1024}'
算出檔案大小(MB)
問題是 用find 通常會需要超過一小時 請問有無適合的方法
感謝
--
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Linux
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